关于js的三级树形菜单
<script language=javascript>function cwin()
{if(parent.testframeset.cols!='200,*')
{parent.testframeset.cols='200,*';
}
else{parent.testframeset.cols='-10,*';
}}
function closenavi() {
w-=10;
if (w>-10) {window.parent.testframeset.cols = ''+w+',*';repeat=setTimeout("closenavi()",100);}
else {clearTimeout(repeat);w=200;}
}
</script>
<body bgcolor="#FFFFFF" text="#000000" scroll=no >
<table id=control width="100%" border="0" cellspacing="0" cellpadding="0" class="borderon">
<tr>
<td height="20" style="padding-top:3px"><nobr> 库的整理</nobr></td>
<td width="20" align="center" valign="top"><img src="images/icon-expandall.gif" width="16" height="15" class="button" vspace="2" alt="全部展开"></td>
<td width="20" align="center" valign="top"><img src="images/icon-close.gif" width="16" height="15" class="button" vspace="2" alt="关闭左栏"></td>
</tr>
</table>
<div id="main1" class="menu" ><table width="100%" border="0" cellspacing="0" cellpadding="0">
<script>t("haha")</script>
</table>
</div>
<div id="page1" class="child" style="padding-left:15px">
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<script>
list("#","_blank","hehe");
list("#","_blank","heihei");
</script>
</table>
</div>
求救：该怎样写，才能成为三级树形菜单！
现在的是二级树形菜单
[[i] 本帖最后由 yanwei8574 于 2007-9-1 13:47 编辑 [/i]] 怎么没有人帮我解决啊？ 比较难啊~~~~~~~~ 我想帮你
#@jcwcn^@@#
但是我看不懂#@#$#%$ 用现在的DWcs3直接就可以做了
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